BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

2m x 2m x 16m storage space

Expert replies
by bhumika.k.shah » Thu Apr 01, 2010 10:49 am
What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
Join the discussion
Source: — Problem Solving |

by outreach » Thu Apr 01, 2010 11:05 am
D)21

(2m x 2m x 16m )/(1m x 1m x 3m )= 21.33
-------------------------------------
--------------------------------------
General blog
https://amarnaik.wordpress.com
MBA blog
https://amarrnaik.blocked/
Join the discussion

by bhumika.k.shah » Thu Apr 01, 2010 11:06 am
nopes
outreach wrote:D)21

(2m x 2m x 16m )/(1m x 1m x 3m )= 21.33
Join the discussion

by harshavardhanc » Thu Apr 01, 2010 12:01 pm
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C. 4 columns having 5 small cubes each
Last edited by harshavardhanc on Thu Apr 01, 2010 12:05 pm, edited 1 time in total.
Regards,
Harsha
Join the discussion

by bhumika.k.shah » Thu Apr 01, 2010 12:02 pm
How ?
Technique ?
Different Approaches ?
Difficulty level ?

P.s.: OA C
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C.
Join the discussion

by harshavardhanc » Thu Apr 01, 2010 12:08 pm
bhumika.k.shah wrote:How ?
Technique ?
Different Approaches ?
Difficulty level ?

P.s.: OA C
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C.
original post edited with technique.

difficulty level : Don't care :)

https://www.beatthegmat.com/mba/2010/03/ ... n-the-gmat
Regards,
Harsha
Join the discussion

by bhumika.k.shah » Thu Apr 01, 2010 12:18 pm
Please explain in detail.

Thanks.
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C. 4 columns having 5 small cubes each
Join the discussion

by ajith » Thu Apr 01, 2010 12:26 pm
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
You can fill 2*2 cross section with four 1*1 crate of length 3m. You can stack it 4 more times so that total length is less than 16

Total no of crates = 5*4 = 20

[you cannot do anything with the 2*2*1 space left]
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by newton9 » Thu Apr 01, 2010 12:27 pm
You can have five rows of 1 x 1 x 3 cubes.

For each row you can have 4 cubes. once front and back and 2 more on top of both of those.

So 5 * 4 = 20 cubes in total.
Join the discussion

by harshavardhanc » Thu Apr 01, 2010 12:30 pm
bhumika.k.shah wrote:Please explain in detail.

Thanks.
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C. 4 columns having 5 small cubes each
ok.

Keeping one small cube over the another, what is the maximum number of small cubes that you can put, so that they don't
cross the 16 unit limit? Remember, each small cube is 3 unit high and you cannot cut it.

5 right? in that case, the height of the column will be 15 units.

now the base of bigger cube is 4 Sq. units and the base of one such column is 1 sq unit. So, you can have 4 such columns
within the bigger cube.

Therefore, total number of smaller cubes will be 4 * 5 = 20.

Let me know if you find anything hazy in the explanation above.
Regards,
Harsha
Join the discussion

by ck_ey » Thu Apr 01, 2010 12:34 pm
I looked at it as how many units can you put in each dimension:

(2m/1m) x (2m/1m) x (16m/3m)

Since we can only have whole numbers of crates (can't have parts of the crates sticking out - in any dimension) it turns out to be:

2 x 2 x 5 = 20. Answer C.
Join the discussion

by bhumika.k.shah » Thu Apr 01, 2010 12:35 pm
i like ! :-)
this is how i tried solving. just wanted to make sure whether my reasoning was correct. thanks!
ck_ey wrote:I looked at it as how many units can you put in each dimension:

(2m/1m) x (2m/1m) x (16m/3m)

Since we can only be whole numbers (we can have parts of the crates sticking out - in any dimension) it turns out to be:

2 x 2 x 5 = 20. Answer C.
Join the discussion