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2m x 2m x 16m storage space

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Source: — Problem Solving |

by outreach » Thu Apr 01, 2010 11:05 am
D)21

(2m x 2m x 16m )/(1m x 1m x 3m )= 21.33
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by bhumika.k.shah » Thu Apr 01, 2010 11:06 am
nopes
outreach wrote:D)21

(2m x 2m x 16m )/(1m x 1m x 3m )= 21.33
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by harshavardhanc » Thu Apr 01, 2010 12:01 pm
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C. 4 columns having 5 small cubes each
Last edited by harshavardhanc on Thu Apr 01, 2010 12:05 pm, edited 1 time in total.
Regards,
Harsha
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by bhumika.k.shah » Thu Apr 01, 2010 12:02 pm
How ?
Technique ?
Different Approaches ?
Difficulty level ?

P.s.: OA C
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C.
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by harshavardhanc » Thu Apr 01, 2010 12:08 pm
bhumika.k.shah wrote:How ?
Technique ?
Different Approaches ?
Difficulty level ?

P.s.: OA C
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C.
original post edited with technique.

difficulty level : Don't care :)

https://www.beatthegmat.com/mba/2010/03/ ... n-the-gmat
Regards,
Harsha
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by bhumika.k.shah » Thu Apr 01, 2010 12:18 pm
Please explain in detail.

Thanks.
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C. 4 columns having 5 small cubes each
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by ajith » Thu Apr 01, 2010 12:26 pm
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
You can fill 2*2 cross section with four 1*1 crate of length 3m. You can stack it 4 more times so that total length is less than 16

Total no of crates = 5*4 = 20

[you cannot do anything with the 2*2*1 space left]
Always borrow money from a pessimist, he doesn't expect to be paid back.
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by newton9 » Thu Apr 01, 2010 12:27 pm
You can have five rows of 1 x 1 x 3 cubes.

For each row you can have 4 cubes. once front and back and 2 more on top of both of those.

So 5 * 4 = 20 cubes in total.
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by harshavardhanc » Thu Apr 01, 2010 12:30 pm
bhumika.k.shah wrote:Please explain in detail.

Thanks.
harshavardhanc wrote:
bhumika.k.shah wrote:What is the maximum number of 1m x 1m x 3m crates that can fit squarely into a 2m x 2m x 16m storage space?

(A) 18
(B) 19
(C) 20
(D) 21
(E) 22

Source KNEWTON CAT
IMO C. 4 columns having 5 small cubes each
ok.

Keeping one small cube over the another, what is the maximum number of small cubes that you can put, so that they don't
cross the 16 unit limit? Remember, each small cube is 3 unit high and you cannot cut it.

5 right? in that case, the height of the column will be 15 units.

now the base of bigger cube is 4 Sq. units and the base of one such column is 1 sq unit. So, you can have 4 such columns
within the bigger cube.

Therefore, total number of smaller cubes will be 4 * 5 = 20.

Let me know if you find anything hazy in the explanation above.
Regards,
Harsha
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by ck_ey » Thu Apr 01, 2010 12:34 pm
I looked at it as how many units can you put in each dimension:

(2m/1m) x (2m/1m) x (16m/3m)

Since we can only have whole numbers of crates (can't have parts of the crates sticking out - in any dimension) it turns out to be:

2 x 2 x 5 = 20. Answer C.
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by bhumika.k.shah » Thu Apr 01, 2010 12:35 pm
i like ! :-)
this is how i tried solving. just wanted to make sure whether my reasoning was correct. thanks!
ck_ey wrote:I looked at it as how many units can you put in each dimension:

(2m/1m) x (2m/1m) x (16m/3m)

Since we can only be whole numbers (we can have parts of the crates sticking out - in any dimension) it turns out to be:

2 x 2 x 5 = 20. Answer C.
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