please show the steps

[daretodream]

(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?

[harsh.champ]

(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?

L.H.S. = (1/5)^m x (1/2)^36

R.H.S. = (1/2)^36 x (1/5)^m

Hence,m=35.

[ajith]

(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?

(1/5)^m x (1/4)^18 = 1/(2(10)^35

1/(5^m*4^18) = 1/(2(10)^35)

1/(5^m*2^36) = 1/(2(10)^35)

1/(5^m*2^36) = 1/2(5*2)^35

1/(5^m*2^36) = 1/2(5^35*2^35)

1/(5^m*2^36) = 1/(5^35*2^36)

m =35

[shashank.ism]

(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?

Again its a similar problem....just make the base common
(1/5)^m x (1/4)^18 = 1/(2(10)^35)
---> (1/5)^m x (1/2)^36 = 1/(2(2x5)^35)
--> (1/5)^m x (1/2)^36 = 1/(2^36 x 5^35)
[spoiler]Ans m= 35[/spoiler]

[thephoenix]

(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?

2*(10^35)=2*2^35 * 5^35=2^36*5^35

now lhs=5^m *4^18=5^m*2^36

equating RHS and LHS
m=35