(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?
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daretodream
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harsh.champ
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L.H.S. = (1/5)^m x (1/2)^36daretodream wrote:(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?
R.H.S. = (1/2)^36 x (1/5)^m
Hence,m=35.
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ajith
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(1/5)^m x (1/4)^18 = 1/(2(10)^35daretodream wrote:(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?
1/(5^m*4^18) = 1/(2(10)^35)
1/(5^m*2^36) = 1/(2(10)^35)
1/(5^m*2^36) = 1/2(5*2)^35
1/(5^m*2^36) = 1/2(5^35*2^35)
1/(5^m*2^36) = 1/(5^35*2^36)
m =35
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shashank.ism
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Again its a similar problem....just make the base commondaretodream wrote:(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?
(1/5)^m x (1/4)^18 = 1/(2(10)^35)
---> (1/5)^m x (1/2)^36 = 1/(2(2x5)^35)
--> (1/5)^m x (1/2)^36 = 1/(2^36 x 5^35)
[spoiler]Ans m= 35[/spoiler]
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thephoenix
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2*(10^35)=2*2^35 * 5^35=2^36*5^35daretodream wrote:(1/5)^m x (1/4)^18 = 1/(2(10)^35
solve for m, m=?
now lhs=5^m *4^18=5^m*2^36
equating RHS and LHS
m=35
