another one

[iamtrying]

. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(c)34
d)28
e)10

i am thinking answer is (E). Correct?

[countingdolls]

No.
(A)

take M as (6n + 1), N as (6n+3).
so, M+N= 2(6n) + 4.

now all you have to do is choose that option which isnt greater than a multiple of 6 by 4.So, 86.

[anandsebastin]

. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(c)34
d)28
e)10

i am thinking answer is (E). Correct?

I'm afraid not. Answer is A.

M+N = (6x+1)+(6y+3)
=6(x+y)+4

So, all possible values of M+N should satisfy, (M+N) - 4/6 = integer.

Applying this test, you'll see that B,C,D and E satisfy this equation.

As for your conclusion, when you divide 3 by 6, remainder is 3, right?

[veer_jy]

(A) sounds correct!