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another one

This topic has 3 member replies
iamtrying Newbie | Next Rank: 10 Posts Default Avatar
Joined
21 Aug 2006
Posted:
8 messages

another one

Post Tue Oct 17, 2006 9:29 am
. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(c)34
d)28
e)10

i am thinking answer is (E). Correct?

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veer_jy Newbie | Next Rank: 10 Posts Default Avatar
Joined
18 Oct 2006
Posted:
2 messages
Post Wed Oct 18, 2006 7:38 pm
(A) sounds correct!

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anandsebastin Junior | Next Rank: 30 Posts Default Avatar
Joined
13 Oct 2006
Posted:
10 messages
Post Wed Oct 18, 2006 6:35 pm
iamtrying wrote:
. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(c)34
d)28
e)10

i am thinking answer is (E). Correct?
I'm afraid not. Answer is A.

M+N = (6x+1)+(6y+3)
=6(x+y)+4

So, all possible values of M+N should satisfy, (M+N) - 4/6 = integer.

Applying this test, you'll see that B,C,D and E satisfy this equation.

As for your conclusion, when you divide 3 by 6, remainder is 3, right? Wink

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countingdolls Junior | Next Rank: 30 Posts Default Avatar
Joined
02 Oct 2006
Posted:
13 messages
Post Tue Oct 17, 2006 10:12 am
No.
(A)

take M as (6n + 1), N as (6n+3).
so, M+N= 2(6n) + 4.

now all you have to do is choose that option which isnt greater than a multiple of 6 by 4.So, 86.

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