raghavsarathy wrote:gmat740 wrote:
and tan 60 = Y-coordinate/X-coordinate
And tan 60 = sq-rt(3) = sq-rt(3)/1
Hi Karan
Sorry to ge this topic again.. How do you know that the value of X-coordinate is 1 (The highlighted part)? It is not mentioned anywhere.
It is a simple ratio. So if the denominator is 1(X-coordinate), then the numerator will be sq-rt(3)
However, since it is a ration, can always say that X-coordinate(denominator) can be 2. I would agree to that, only if the numerator becomes 2 times sq-rt(3). Becoz we have to keep the ratio of Numerator/denominator = Sq-rt(3)
I took the simple ratio and got 1= denominator.
lets say that there are two answers given which are x=1 and x=2, so now which one would you choose??
If you look P(r,s).The distance between P and O(center) = 2(there is formula for calculating distance between 2 points whose whose coordinates are given, I am not going into that detail)
distance between P and O(center) is actually radius.So the max value of x-coordinate on the positive X side(Q-side) will be 2.
However, when X=2, Y-coordinate =0.
But we know the simple ratio has to be sq-rt(3). So definitely x=2 is not the answer.
Hope this long post clears all your doubts