BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

DS

Expert replies
by ankanas » Tue Aug 07, 2007 9:35 pm
Figure ABCD is a rectangle with sides of length x centimeters and width y centimeters, and a diagonal of length z centimeters. What is the measure, in centimeters, of the perimeter of ABCD

(1) x-y= z
(2)z=13

The answer is C :?
Join the discussion
Source: — Data Sufficiency |

Question

by gmatz » Wed Aug 08, 2007 7:03 am
Did you copy the question correctly? Please check the first statement to see if it is x+y=z. Thanks.
Join the discussion

by gabriel » Wed Aug 08, 2007 7:49 am
@ ankanas .. DS questions go in the DS section ..

@ gmatz .. i have deleted the 2 extra posts that u posted ...

PS : - Welcome to BTG both of you :D ..
Join the discussion

by karthick451 » Wed Aug 08, 2007 10:44 am
Looks like there is something wrong with the question. If not, I'm missing something very obvious here.

Since z is the diagonal, it has to be largest side formed by the triangle xyz.

But x-y = z implies that x is greater than z.
Join the discussion

by bingojohn » Wed Aug 08, 2007 1:36 pm
karthick451 wrote:Looks like there is something wrong with the question. If not, I'm missing something very obvious here.

Since z is the diagonal, it has to be largest side formed by the triangle xyz.

But x-y = z implies that x is greater than z.
Thats right. The question seems wrong. Here is why, mathematically:

x - y = z ...........(a)
x^2 + y^2 = z^2 ...........(b)

squaring both sides of (a), we get:
x^2 + y^2 - 2xy = z^2 .........(c)

subtracting (c) from (b), we get:
2xy = 0

which is impossible, unless ABCD is a line instead of a rectangle.

The explanation provided by some 'guest' above is wrong in more than one places...

The square root of x^2-2xy+y^2 is (x+y) NOPE, its x-y
x^2-2xy+y^2=49 where did you get the 49 from? Thats not a 7, thats a z as in zebra...
Join the discussion

by ankanas » Wed Aug 08, 2007 6:57 pm
Oh...! I forgot to log in when I posted the solution..

Well, I too was not able to figure out how x^2-2xy+y^2=49.. The reason why I posted it here. Looks like the question is wrong...!

Thanks...!

Ankana
Join the discussion