BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

rented car

Expert replies
by LevelOne » Mon Jun 22, 2009 12:42 pm
Three friends rented a car for a week and divided the cost equally. What was the total cost of renting the car?

(1) if the three friends had kept the car for a second week, they could have obtained the two-week rate, which was 1.5 times the cost of one-week rental.
(2) if a fourth friend had joined the three friends and the cost had been divided equally among the four friends, the cost to each of the original three would have been reduced by $15.

(1) does not arise any questions to me; (2) would the equation look like:

x + (x-15) + (x-15) + (x-15)=100

?? thanks
Join the discussion
Source: — Data Sufficiency |

by abhinav85 » Mon Jun 22, 2009 12:47 pm
IMO B

What is the OA???
Join the discussion

by LevelOne » Mon Jun 22, 2009 12:50 pm
OA is B. What are your thoughts on the equation in (2)?
Join the discussion

Re: rented car

by PussInBoots » Mon Jun 22, 2009 12:52 pm
LevelOne wrote:Three friends rented a car for a week and divided the cost equally. What was the total cost of renting the car?

(1) if the three friends had kept the car for a second week, they could have obtained the two-week rate, which was 1.5 times the cost of one-week rental.
Definitely not sufficient enough by itself
LevelOne wrote:(2) if a fourth friend had joined the three friends and the cost had been divided equally among the four friends, the cost to each of the original three would have been reduced by $15.
x - how much three friends paid. Total cost = 3*x
after their friend joined, three friends paid x-15. Total cost = 4 *(x-15)
3x = 4x - 60 => x=60. Total cost = 180
So (A), (C) and (E) are wrong answers. Since (1) is not sufficient enough, (D) is wrong too.

The answer is (B)
Join the discussion

by LevelOne » Mon Jun 22, 2009 1:04 pm
it says 'the cost to each of the original three would have been reduced by $15.

you say: Total cost = 4 *(x-15). it looks like you are reducing the cost of the 4th one by 15 as well. pls explain.
Join the discussion

by rahulg83 » Mon Jun 22, 2009 1:36 pm
Hi

If x is the total cost of renting, then it will cost x/3 too each of the three friends. But if fourth person joins them, each will have to expend x/4
now x/3-x/4 = 15
=> x= 12*15 = 180
therefore statement 2 is sufficient..B
Join the discussion

by LevelOne » Mon Jun 22, 2009 10:25 pm
thanks, guys
Join the discussion