It is a 30-60-90 triangle so PS = 4 and PQ = 8
SInce it is a equilateral triangle, 8*3 = 24
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Source: Beat The GMAT — Problem Solving |
I doubt the solution
In an equilateral triangle :
Altitude or Height = sqrt(3)/2 times of a
where a= side of the equilateral triangle(this can be easily proved with the help of trigonometry)
So 4/sqrt(3) = [sqrt(3)/2]*a
a = 8/3
So perimeter = 3a = 8
Please check again
Thanks
In an equilateral triangle :
Altitude or Height = sqrt(3)/2 times of a
where a= side of the equilateral triangle(this can be easily proved with the help of trigonometry)
So 4/sqrt(3) = [sqrt(3)/2]*a
a = 8/3
So perimeter = 3a = 8
Please check again
Thanks
Bold statement above .. incorrectly written.. its 4root(3) and not 4/root(3)gmat740 wrote:I doubt the solution
In an equilateral triangle :
Altitude or Height = sqrt(3)/2 times of a
where a= side of the equilateral triangle(this can be easily proved with the help of trigonometry)
So 4/sqrt(3) = [sqrt(3)/2]*a
a = 8/3
So perimeter = 3a = 8
Please check again
Thanks
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