Ps- It was time consuming

[jeevan.Gk]

Pls explain the approach...

Other than trial and error approach. And note down the time you take.
Let me know if its a question to skip.

[sureshbala]

Let the population of the least district be x.

Now the maximum population of any other district is 110%(x).

Now x will be minimum if the population of the rest of the districts is maximum.

Hence for x to be minimum the population of each of the other 10 districts must be 110%(x).

Given that x + 10[110%(X)]= 132,000
i.e 12x = 132,000.
x=11,000

[x2suresh]

Let the population of the least district be x.

Now the maximum population of any other district is 110%(x).

Now x will be minimum if the population of the rest of the districts is maximum.

Hence for x to be minimum the population of each of the other 10 districts must be 110%(x).

Given that x + 10[110%(X)]= 132,000
i.e 12x = 132,000.
x=11,000

Agree with you.

Nice work

[ven4gmat]

Let the population of the least district be x.

Now the maximum population of any other district is 110%(x).

Now x will be minimum if the population of the rest of the districts is maximum.

Hence for x to be minimum the population of each of the other 10 districts must be 110%(x).

Given that x + 10[110%(X)]= 132,000
i.e 12x = 132,000.
x=11,000

ohh...you made it seem simple to me man...initially i was also a bit confused to tackle this question..