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Work problem

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Source: — Problem Solving |

by sureshbala » Tue Feb 24, 2009 3:14 am
If money charged by M is 6 $, then money charged by P and K will 2$ and 1$ respectively.

Since the money is divided in the ratio of the work contributed by them, the work contributed by M, P and K is in the ratio 6:2:1.

So the time charged by M is 6/9 x(162) and by K is 1/9(162).

Hence the difference = 5/9(162) = 90 hrs
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