Ds qusetion

[jamesk486]

If y>0, what is the value of x?
1. |x-3|>y
2. |x-3|<-y

i'm a bit confused about condition 2 bc even if |x-3| must be positive, how can it be less than -y which is negative since y>0 ?

[gabriel]

If y>0, what is the value of x?
1. |x-3|>y
2. |x-3|<-y

i'm a bit confused about condition 2 bc even if |x-3| must be positive, how can it be less than -y which is negative since y>0 ?

chk the question again ... i bet it says y is > or equal to 0 ..

[Cybermusings]

This question is not posted correctly

We already know that y>0....hence -y would be negative....now Ix-3I will always be positive....So how can Ix-3I be ever less than -y???

[f2001290]

Second statement is <=