If y>0, what is the value of x?
1. |x-3|>y
2. |x-3|<-y
i'm a bit confused about condition 2 bc even if |x-3| must be positive, how can it be less than -y which is negative since y>0 ?
Ds qusetion
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- gabriel
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jamesk486 wrote:If y>0, what is the value of x?
1. |x-3|>y
2. |x-3|<-y
i'm a bit confused about condition 2 bc even if |x-3| must be positive, how can it be less than -y which is negative since y>0 ?
chk the question again ... i bet it says y is > or equal to 0 ..
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This question is not posted correctly
We already know that y>0....hence -y would be negative....now Ix-3I will always be positive....So how can Ix-3I be ever less than -y???
We already know that y>0....hence -y would be negative....now Ix-3I will always be positive....So how can Ix-3I be ever less than -y???