I feel answer is E
1) Suppose x=1.9 then still the given equation is greater than 0..and x< 3
2) Not sufficient as explained above..
Combining both of them Not sufficient.
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inequality
Source: Beat The GMAT — Data Sufficiency |
To prove X >3.
1) (X-3) (X-2) (X-1) >0
To make this hapenne..
1. X should not equal to 3 or 2 or 1.
2. either all of then are +ve or at least 2 of them are -ve.
But cant say whether X>3 or not, because for X=4 this relation is true, but it is also tru for X=1.7. so NOT SUFF
2) X>1, simpally X=2 is false but x=4 is true for the statement given. so NOT SUFF
but combining both will say this,
X>1 and X is not 1,2,3 it means x>3.
Ans : C
1) (X-3) (X-2) (X-1) >0
To make this hapenne..
1. X should not equal to 3 or 2 or 1.
2. either all of then are +ve or at least 2 of them are -ve.
But cant say whether X>3 or not, because for X=4 this relation is true, but it is also tru for X=1.7. so NOT SUFF
2) X>1, simpally X=2 is false but x=4 is true for the statement given. so NOT SUFF
but combining both will say this,
X>1 and X is not 1,2,3 it means x>3.
Ans : C
Shubham.
590 >> 630 >> 640 >> 610 >> 600 >> 640 >> 590 >> 640 >> 590 >> 590
590 >> 630 >> 640 >> 610 >> 600 >> 640 >> 590 >> 640 >> 590 >> 590
Is x-3 > 0
1. (x-3) (x-2) (x-1) > 0
- - +
+ + +
are the only two ways we can have a positive product
we don't know which so INSUF
2. x>1[/quote]
Hmm
x-1> 0 means
x>1 so we still can not find out whether x>3 ( on another note, if this option was x>4 , we would choose B )
1+2 together
- - +
+ + +
so we have one POSITIVE for sure so we are left with
- - or + +
we now that x >1 but if it is less than 2
we will have
- -
if x is greater than 3 we will have
+ +
Do we know anything about where x lies ? NO
E
1. (x-3) (x-2) (x-1) > 0
- - +
+ + +
are the only two ways we can have a positive product
we don't know which so INSUF
2. x>1[/quote]
Hmm
x-1> 0 means
x>1 so we still can not find out whether x>3 ( on another note, if this option was x>4 , we would choose B )
1+2 together
- - +
+ + +
so we have one POSITIVE for sure so we are left with
- - or + +
we now that x >1 but if it is less than 2
we will have
- -
if x is greater than 3 we will have
+ +
Do we know anything about where x lies ? NO
E
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
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"DON'T LET ANYONE STEAL YOUR DREAM!"
This is a very nice solution but we are NOT told that X can be only integer.welcome wrote:To prove X >3.
1) (X-3) (X-2) (X-1) >0
To make this hapenne..
1. X should not equal to 3 or 2 or 1.
2. either all of then are +ve or at least 2 of them are -ve.
But cant say whether X>3 or not, because for X=4 this relation is true, but it is also tru for X=1.7. so NOT SUFF
2) X>1, simpally X=2 is false but x=4 is true for the statement given. so NOT SUFF
but combining both will say this,
X>1 and X is not 1,2,3 it means x>3.
Ans : C
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
logitech,
Where is this mentioned that X should be an integer. Or it is some kind of rule or assumption. Please tell me the details.
Thanks in advance.
Where is this mentioned that X should be an integer. Or it is some kind of rule or assumption. Please tell me the details.
Thanks in advance.
Shubham.
590 >> 630 >> 640 >> 610 >> 600 >> 640 >> 590 >> 640 >> 590 >> 590
590 >> 630 >> 640 >> 610 >> 600 >> 640 >> 590 >> 640 >> 590 >> 590
Well nothing is mentioned about X so it can be any number. Fraction or integer.welcome wrote:logitech,
Where is this mentioned that X should be an integer. Or it is some kind of rule or assumption. Please tell me the details.
Thanks in advance.
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
