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vittalgmat
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Stmt I
-M = |-M|
Take any positive value this will not be true
M= 2
-M = -2
|-M| = |-2| = 2
-M <> |-M|
It will be true for only 0 and negative values
M=-2
-M = -(-2) = 2
|-M| = |-(-2)| = |2| = 2
-M = |-M|
I am sure u got smt II insufficiency already
Using stmt II together wiht stmt I u cal eliminate M being 0 or +3 therefore M is negative and < 0.
Hope this helps!

















