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sanju09
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x = 1 in A doesn't give a 3, outGurpinder wrote:
x = 2 in B doesn't give a 10, out
x = 1 in C doesn't give a 3, out
x = 1 in D doesn't give a 3, out
run away with [spoiler]E[/spoiler] man
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
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Gurpinder
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guys,
sorry to sound like a dumb *** but i am lost with the question.
I think more than anything, i dont understand the question?!?!?!
please explain!
Thx.
sorry to sound like a dumb *** but i am lost with the question.
I think more than anything, i dont understand the question?!?!?!
please explain!
Thx.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
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debmalya_dutta
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Let me try ...Gurpinder wrote:guys,
sorry to sound like a dumb *** but i am lost with the question.
I think more than anything, i dont understand the question?!?!?!
please explain!
Thx.
So what the question says is that you have some cards which you arrange in a certain order . The value of the card is based on the position of the card in the arrangement / order in which you arrange.. For example you have 3 cards
Ist Position - C1 (value of this card is based on its position which 1 . So , the value is some function of x, f(x) - where x is the position of the card .. here you dont know what f(x) is but whatever it is you want to find f(1))
2nd position - C2(value of this card is based on its position which 2 . So , the value is some function of x, f(x) - where x is the position of the card .. here you dont know what f(x) is but whatever it is you want to find f(2))
Third position - C3 (same as above)
@Deb
