BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Another co-geo problem!

Expert replies
Source: — Problem Solving |

by neelgandham » Tue Nov 01, 2011 6:32 am
For x=0, we know that y>0
For y=0, we know that x>0

1) 2x-3y=6; x=0 => y=-2 Not the answer
2) 2x+3y=6; x=0 => y=2 May be. y=0 => x=3 May be.
3) 3x+2y=6; x=0 => y=3 May be. y=0 => x=2 May be. But in the diagram, x>2..Not the answer
4) 2x-3y=-6; x=0 => y=2 May be. y=0 => x=-3..Not the answer
5) 3x-2y=-6; x=0 => y=3 May be. y=0 => x=-2..Not the answer

Option B
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Join the discussion

by rijul007 » Tue Nov 01, 2011 6:37 am
line l is supposed to have a negative slope.

for a line
ax + by = c

slope = -b/a

in this case...
option A,D and E are eliminated becouse there slope is positive.




now in the figue
x- intercept is longer than the y- intercept


which can be represented by the eq in option B
Last edited by rijul007 on Tue Nov 01, 2011 6:49 am, edited 1 time in total.
Join the discussion

by GMATGuruNY » Tue Nov 01, 2011 6:42 am
Image

Another approach:

Traveling from the y intercept to the x intercept:
Rise = -2.
Run = 3.
Thus, slope = -2/3.

Since the y intercept = 2, we get the following:
y = (-2/3)x + 2
3y = -2x + 6
2x + 3y = 6.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by shankar.ashwin » Tue Nov 01, 2011 6:56 am
I had posted this for a different problem, but it would help in this case as well. Looking at the line you could frame the equation.
Read the last part

https://www.beatthegmat.com/x-intercept- ... tml#417295
Join the discussion

by user123321 » Tue Nov 01, 2011 11:16 am
if you know intercepts then line equation is x/a + x/b = 1

so x/3+y/2 = 1 => 2x+3y = 6

user123321
Just started my preparation :D
Want to do it right the first time.
Join the discussion

by LalaB » Tue Nov 01, 2011 1:02 pm
from the pic we can see ,that our line has a negative slope.
so, A ;D; E are out. now we have only 2 choices- either B, or C.

return to the pic. we see that (3;0) is a point of this line. applying this to our two equations we can assume, that B is our answ
Join the discussion

by vaibhavgupta » Wed Nov 02, 2011 1:55 pm
GmatKiss wrote:Please help to solve!

find slope.. and then take one of the points in the eq. y=mx+b where m=slope and b=y intercept

B it is! :)
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
Join the discussion

by vaibhavgupta » Wed Nov 02, 2011 1:56 pm
GmatKiss wrote:Please help to solve!

find slope.. and then take one of the points in the eq. y=mx+b where m=slope and b=y intercept

B it is! :)
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
Join the discussion