venn diagram?

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jopup: Junior | Next Rank: 30 Posts; Posts: 28; Joined: Sat Jun 14, 2008 5:12 am; Thanked: 1 times

by jopup » Sun Jun 15, 2008 7:18 pm

students in the caf either like or dislike lima beans and brussel sprouts.
of these students 2/3 dislike llima beans, and of these 5/8 also dislike brussel sprouts, how many students like brussel sprouts but hate lima beans.

1. 120 students
2 40 like lima beans

is the answer 88?

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Source: Beat The GMAT — Data Sufficiency | Sun Jun 15, 2008 7:18 pm

netigen: Legendary Member; Posts: 631; Joined: Mon Feb 18, 2008 11:57 pmFollowed by: 3 members; Thanked: 29 times

by netigen » Sun Jun 15, 2008 7:39 pm

Ans is E

insufficient to answer the Q

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anshul265: Senior | Next Rank: 100 Posts; Posts: 71; Joined: Thu Jan 31, 2008 7:01 am; Thanked: 2 times

by anshul265 » Sun Jun 15, 2008 7:40 pm

It will surely not be 88. The total number of student who dislike Lima beans is 80. Both from 1 and 2.

Is the answer E?

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ildude02: Master | Next Rank: 500 Posts; Posts: 320; Joined: Sun Jan 13, 2008 10:00 pm; Thanked: 10 times

Re: venn diagram?

by ildude02 » Mon Jun 16, 2008 12:00 pm

jopup wrote:students in the caf either like or dislike lima beans and brussel sprouts.
of these students 2/3 dislike llima beans, and of these 5/8 also dislike brussel sprouts, how many students like brussel sprouts but hate lima beans.

1. 120 students
2 40 like lima beans

is the answer 88?

Can someone expain how to solve this problem? I figured that the answer is E, but I wasn't comfortable with my approach. If x is total students, =>, 2/3x = DB(dislike beans), 5/8(2/3x) = 5/12x (DB+DS) . We cna eliminate (2) for sure as INSUFF. Considering (1), 80 = DB, 50 = DB+ DS(dislike sprouts). I didn't get any number for likes, but I wanted to know if my approach is right , and if there is a better way to approach this problem and how you would solve it.

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sanjaylakhani: Senior | Next Rank: 100 Posts; Posts: 47; Joined: Wed Apr 30, 2008 8:13 pm

by sanjaylakhani » Fri Jun 20, 2008 7:34 pm

Hi

The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.

Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)

so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer

As per above , D should be answer

can anyone explain what's wrong here

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durgesh79: Master | Next Rank: 500 Posts; Posts: 167; Joined: Tue Apr 22, 2008 12:48 am; Thanked: 15 times

by durgesh79 » Fri Jun 20, 2008 8:35 pm

sanjaylakhani wrote:Hi

The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.

Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)

so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer

As per above , D should be answer

can anyone explain what's wrong here

I think you are right, both statement 1 and 2 are giving same information.....

I made a venn diagram ... and i think the answer should be D...

OA Please

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albertrahul: Senior | Next Rank: 100 Posts; Posts: 83; Joined: Wed Jun 04, 2008 3:30 am; Thanked: 4 times

by albertrahul » Sat Jun 21, 2008 6:41 am

This question could be solved by Venn diagram.

Statement 1 says: Total students = 120.

Hence: Students who dislike Lima Beans = 120 * 2/3 = 80
Out of these, students who dislike Sprouts = 80 * 5/8 = 50
So total students who like sprouts but dislike beans = 80-50 = 30

So statement 1 is sufficient

Statement 2 says: 40 like Lima beans.
Hence 40 = 1/3 of total students, so total students = 120.
We can follow similar logic as above.
This statement is sufficient as well.

Answer IMO = D.

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rakesheval: Newbie | Next Rank: 10 Posts; Posts: 8; Joined: Sat Jun 21, 2008 7:56 am

by rakesheval » Sat Jun 21, 2008 8:59 am

answer is d..make a venn diagram..that should be helpful..

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