If (y+3)(y-1) – (y-2)(y-1) = r(y-1), what is the value of y?
(1) r^2 = 25
(2) r = 5
IMO A
Value problem
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y^2-y+3y-3 - [ y^2 - y -2y +2 ] = r(y-1)arorag wrote:If (y+3)(y-1) – (y-2)(y-1) = r(y-1), what is the value of y?
(1) r^2 = 25
(2) r = 5
IMO A
y^2 +2y -3 - y^2 + 3y -2 =r(y-1)
5y - 5 = r(y-1)
5(y-1) = r(y-1)
r=5
Statement I
r^2 = + or -5
if r=-5
5(y-1) = -5(y-1)
5y-5 = -5y +5
y=1
or
if r=5
5(y-1) = 5y-5
y could be anything 1,2,3, anything
Insufficient.
Statement II
r=5
y could be anything 1,2,3 anything
Insufficient.
Combining I & II
r=5
y could be anything, 1 ,2,3,4, 0.5
Insufficient.
Hence the answer should be E.
Whats the OA?
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What is the source of this Q? I think it is little bit crooked
From the main statement we have
r=5 - and this should be not changable
(1)
gives us r = +/- 5
but we have r = 5
5(y-1) = 5y-5 - nothing definite
Thus, INSUFF
(2)
r=5
Yeh, good news! We knew it!!!
So what? 5(y-1) = 5y-5 - nothing definite once again!
INSUFF
Answer E
By the way, I think that should be read in such way:
If (y+3)(y-1) + (y-2)(y-1) = r(y-1), what is the value of y?
(1) r^2 = 25
(2) r = 5
with answer B
arorag, could you please check?
From the main statement we have
r=5 - and this should be not changable
(1)
gives us r = +/- 5
but we have r = 5
5(y-1) = 5y-5 - nothing definite
Thus, INSUFF
(2)
r=5
Yeh, good news! We knew it!!!
So what? 5(y-1) = 5y-5 - nothing definite once again!
INSUFF
Answer E
By the way, I think that should be read in such way:
If (y+3)(y-1) + (y-2)(y-1) = r(y-1), what is the value of y?
(1) r^2 = 25
(2) r = 5
with answer B
arorag, could you please check?