from 1:
|x-3|>= y, a non-negative number. Since, y it could be any number, x could take various values.
Not Sufficient
from 2:
|x-3|<= -y
since absolute value can never be negative, this is only possible, if y=0.
therefore x-3 = 0, x=3
Sufficient
IMO answer B
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value of x?
Source: Beat The GMAT — Data Sufficiency |
IMO Biamseer wrote:from 1:
|x-3|>= y, a non-negative number. Since, y it could be any number, x could take various values.
Not Sufficient
from 2:
|x-3|<= -y
since absolute value can never be negative, this is only possible, if y=0.
therefore x-3 = 0, x=3
Sufficient
IMO answer B
oops it has to be B. Seer explanation does all!
Last edited by gmatmachoman on Sat May 08, 2010 11:31 am, edited 1 time in total.
Ans: B
Since, | x -3 | >= 0 always true hence not sufficient.
|x -3| <= -y and Y >= 0
LHS is always +ve and rhs is -ve hence it is only satisfied when Y = 0
and hence X = 3
Since, | x -3 | >= 0 always true hence not sufficient.
|x -3| <= -y and Y >= 0
LHS is always +ve and rhs is -ve hence it is only satisfied when Y = 0
and hence X = 3
-
harshavardhanc
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st1: |x - 3| >= yneoreaves wrote:If y > = 0, what is the value of x?
1. |x - 3| >= y
2. |x - 3| <= - y
as y is a positive quantity and |x-3| > y .
implies that x-3 itself is a positive quantity and we can safely write it as x-3 > y . However, this doesn't give us an solid value for X. Hence, insufficient.
st2: |x - 3| <= - y
LHS of this is a modulus, which can be either 0 or positive number. However, on the RHS we have -y. Suppose, y is a non-zero number. In that case, RHS would become a negative quantity and cannot be equated to a modulus . Hence, y MUST be zero.
which will give us |X-3| = 0 or X = 3.
IMO B
Regards,
Harsha
Harsha
