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Units Digit Shortcuts / Patterns

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
by rishimaharaj » Fri Aug 05, 2011 5:56 pm
Hi all,

I was searching around and could not find this information easily, so took a few minutes to throw it together to share in case anyone else needed it.

Units Digit Shortcut / Patterns
1 = [1]
2 = [2,4,8,6]
3 = [3,9,7,1]
4 = [4,6]
5 = [5]
6 = [6]
7 = [7,9,3,1]
8 = [8,4,2,6]
9 = [9,1]
0 = [0]

Some are easy to memorize, such as 1, 4, 5, 6, 9, and 0. The others can be quickly figured out by going through a few powers of the number until it repeats.
For example, let's take a number ending in 3. (I'll use ANEI to mean "a number ending in").
ANEI 3 * ANEI 3 = ANEI 9 (Example: 3*3=9, or 3*13=39)
ANEI 9 * ANEI 3 = ANEI 7 (Example: 9*3=27, or 9*13=117)
ANEI 7 * ANEI 3 = ANEI 1 (Example: 7*3=21, or 17*3=51)
ANEI 1 * ANEI 3 = ANEI 3 (REPEAT!)
So the pattern for ANEI 3 will be [3,9,7,1].

This means that ANEI 3^1,5,9,13,(+4 etc.) will have a Units Digit of 3.
ANEI 3^2,6,10,14,(+4 etc.) will have a Units Digit of 9.
ANEI 3^3,7,11,15,(+4 etc.) will have a Units Digit of 7.
and ANEI 3^4,8,12,16,(+4 etc.) will have a Units Digit of 1.

Example: What is the units digit of 768493023^31?
3 has a pattern containing 4 numbers.
31/4 = 7 r3
The third item in the pattern is 7, thus 768493023^31 will have a units digit of 7.


Another example, this time from the Manhattan GMAT Advanced Gmat Quant book:
If x is a positive integer, what is the units digit of (24)^5+2x (36)^6 (17)^3?
A. 2
B. 3
C. 4
D. 6
E. 8
We can easily find the units digit of 36^6, since ANEI 6 * ANEI 6 = ANEI 6.
For 17^3, the pattern is [7,9,3,1], so the units digit is 3 (since it is the third in the pattern).

24^5+2x isn't as tricky as it seems.
If x=1, then 5+2(1) = 7 (odd)
If x=2, then 5+2(2) = 9 (odd).
So regardless of the value of x, the power is odd.
ANEI 4^(odd power) = ANEI 4. This is because the pattern for 4 is [4 (odd), 6 (even)].

So when we multiply ANEI 6 * ANEI 3 * ANEI 4 = ANEI 8 * ANEI 4 = ANEI 2.
The answer is A.

Hope this comes in handy on test day!
Oh, and if anyone has any information on how to apply this to tens digits or hundreds digits, please share!

Thanks,
--Rishi
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Source: — Quantitative Reasoning |

by sumgb » Sun Aug 14, 2011 8:40 am
Could not understand why
24^5+2x isn't as tricky as it seems.
the question asks the units digit of
(24)^5+2x (36)^6 (17)^3
IMO you should consider units digit of this "2x (36)^6 (17)^3" before adding it to units digit of (24)^5 which is 4.

IMO -
2x (36)^6 (17)^3
Units digit of (36)^6 = 6
Units digit of (17)^3 = 3
multiplied by 2; so far unit digit 6
unit digit of 6 * x depends on the value of x
if x = 1 unit digit = 6
if x = 2 unit digit = 2
if x = 3 unit digit = 8
if x = 4 unit digit = 4
if x = 5 unit digit = 0 and so on..

can you please clarify?

Thanks...
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by rishimaharaj » Sun Aug 14, 2011 1:48 pm
Hello Sumgb,

The problem has three terms:
24, 36, and 17.

24 is to the 5+2x power
36 is to the 6th power
17 is to the 3rd power

So it's [(24)^5+2x] * [(36)^6] * [(17)^3].

I think you're thinking of the problem as:
(24)^ [5+2x * (36)^6 * (17)^3]


Hopes this helps to clarify. Let me know if you still have any doubts!
--Rishi
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by sumgb » Sun Aug 14, 2011 2:26 pm
[(24)^5+2x] * [(36)^6] * [(17)^3].
ah right...

I thought (24)^5 + {2x * (36)^6 * (17)^3}

got it...
Cheers
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