approximation

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kanha81: Master | Next Rank: 500 Posts; Posts: 431; Joined: Sat Jan 10, 2009 9:32 amFollowed by: 1 member; Thanked: 16 times

by kanha81 » Mon Apr 20, 2009 8:10 am

Show your work to receive the credit!

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Source: Beat The GMAT — Problem Solving | Mon Apr 20, 2009 8:10 am

bluementor: Master | Next Rank: 500 Posts; Posts: 418; Joined: Wed Jun 11, 2008 5:29 am; Thanked: 65 times

by bluementor » Mon Apr 20, 2009 8:20 am

(10^8 - 10^2)/(10^7 - 10^3)

= (10^2)*(10^6 - 1)/(10^3)(10^4 - 1)

I will now approximate the following:

(10^6 - 1) ≈ 10^6
(10^4 - 1) ≈ 10^4

So,

(10^2)(10^6)/(10^3)(10^4)
=10^(2+6-3-4)
=10^1
=10

Choose B.

-BM-

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