BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Unable to visualize a specific permutation problem

Expert replies
by jaintanvi » Thu Nov 12, 2009 6:46 am
Hi - I'm having difficulty in visualizing problems of the types where 3 or more elements do NOT have to be together in permutation problems:

Problem 1:
How many ways can the letters of RAINBOW be arranged so that the vowels are never together?
or
Problems 2: How many ways can 6 students and 4 teachers be seated so that no 2 teachers are together?

Now, the answer explanation says that:

Problem 1 - 4 consonant can be arranged in 4! ways which leaves us with 5 places to place the 3 vowels - HOW 5 PLACES?? IT SHOULD BE 3 PLACES, RIGHT?

Problem 2- 6 students can sit in 6! ways, which leaves 7 places to seat the 4 teachers - AGAIN, HOW 7 PLACES??

Please help.
Tanvi
Join the discussion
Source: — Problem Solving |

by palvarez » Thu Nov 12, 2009 9:10 am
XCXCXCXCX

count number of X's in the above = 5


Same with the second problem.
Join the discussion

by antondesh » Thu Nov 12, 2009 11:29 am
Problem 2:

Let's say S = students and _ = empty place where we can put a teacher.

First, line up all the students so there's exactly one gap between each one of them for the teacher.

There are 6 students so:

S_S_S_S_S_S

This gives us 5 spots to put the teachers, right?

But think about the edges! There's 2 more spaces on the edges. If we place a teacher there he'll have an empty space on one side and a student on another which satisfies the condition.

_S_S_S_S_S_S_

So in total, we have 7 spots to put the teachers. Hope this helps!
Join the discussion