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Expert replies
by jsasipriya » Sun Jan 02, 2011 2:14 am
How many different numbers y are there such that Ay+B=C (A ,B , and C are known) ?

1. C>B
2. A>1


OA B
I don't understand the question stem itself. Can someone explain me what the question is?

Thanks!
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Source: — Data Sufficiency |

by Anurag@Gurome » Sun Jan 02, 2011 2:34 am
jsasipriya wrote:How many different numbers y are there such that Ay+B=C (A ,B , and C are known) ?

1. C>B
2. A>1
The question is asking for the number of values of y, which satisfies the relation Ay + B = C, where A, B, and C are known numbers.

Thus from the relation given we can write y as, y = (C - B)/A

Now if A, B and C are known, we can easily determine the value of y only with exception A = 0. Because when A = 0, then the value of y is undefined as y = (C - B)/A.

Statement 1: C > B
Only from this we cannot determine the number of values of y that satisfies the given relation. We need to know whether A is nonzero or not.

Not sufficient.

Statement 2: A > 1
Clearly A is nonzero and thus we can uniquely determine the number of values of y that satisfies the given relation Ay + B = C. In fact only one number is there, which is given by (C - B)/A

Sufficient.

The correct answer is B.
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by bblast » Sun Jan 09, 2011 6:33 am
Anurag@Gurome wrote:
jsasipriya wrote:How many different numbers y are there such that Ay+B=C (A ,B , and C are known) ?

1. C>B
2. A>1
The question is asking for the number of values of y, which satisfies the relation Ay + B = C, where A, B, and C are known numbers.

Thus from the relation given we can write y as, y = (C - B)/A

Now if A, B and C are known, we can easily determine the value of y only with exception A = 0. Because when A = 0, then the value of y is undefined as y = (C - B)/A.

Statement 1: C > B
Only from this we cannot determine the number of values of y that satisfies the given relation. We need to know whether A is nonzero or not.

Not sufficient.

Statement 2: A > 1
Clearly A is nonzero and thus we can uniquely determine the number of values of y that satisfies the given relation Ay + B = C. In fact only one number is there, which is given by (C - B)/A

Sufficient.

The correct answer is B.
hey anurag my question might seem dumb, but this is not a yes/no question, we need to find a value of Y:
so how to we solve for c-b/A and get a solution ?
:?:
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by Anurag@Gurome » Sun Jan 09, 2011 6:43 am
bblast wrote:hey anurag my question might seem dumb, but this is not a yes/no question, we need to find a value of Y:
so how to we solve for c-b/A and get a solution ?
:?:
This is neither a "yes/no" question nor we have to get a solution for y.
The question asks to determine "how many different numbers y are there such that Ay + B = C (A ,B , and C are known)". Thus we have to find number of possible different solutions of y. There is a difference between solving an equation and determining the number of solutions.

On a different note, unless we know the values of A, B, and C, we cannot solve for y.
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by prachich1987 » Mon Jan 10, 2011 7:54 am
what's the source jsasipriya?
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