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Two trains started simultaneously from opposite ends of...

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by AAPL » Tue Dec 26, 2017 3:57 pm
Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5

The OA is A.

I don't have clear this PS question, I appreciate if any expert explain it for me. Thank you so much.
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Source: — Problem Solving |

by Brent@GMATPrepNow » Tue Dec 26, 2017 4:35 pm
AAPL wrote:Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5
One approach:

Train X completed the 100-mile trip in 5 hours
Speed = distance/time
= 100/5
= 20 mph

Train Y completed the 100-mile trip in 3 hours
Speed = distance/time
= 100/3
≈ 33 mph (This approximation is close enough. You'll see why shortly)

How many miles had Train X traveled when it met Train Y?
Let's start with a word equation.

When the two trains meet, each train will have been traveling for the same amount of time
So, we can write: Train X's travel time = Train Y's travel time

time = distance/speed
We know each train's speed, but not the distance traveled (when they meet). So, let's assign some variables.

Let d = the distance train X travels
So, 100-d = the distance train Y travels (since their COMBINED travel distance must add to 100 miles)

We can now turn our word equation into an algebraic equation.
We get: d/20 = (100 - d)/33
Cross multiply to get: (33)(d) = (20)(100 - d)
Expand: 33d = 2000 - 20d
Add 20d to both sides: 53d = 2000
So, d = 2000/53

IMPORTANT: Before you start performing any long division, first notice that 2000/50 = 40
Since the denominator is greater than 50, we can conclude that 2000/53 is LESS THAN 40
Since only one answer choice is less than 40, the correct answer must be A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by GMATGuruNY » Tue Dec 26, 2017 5:36 pm
AAPL wrote:Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5
Time and rate have a RECIPROCAL RELATIONSHIP.
If Mary works TWICE as fast as John, Mary's time will be 1/2 John's time.
If Mary works THREE TIMES as fast as John, Mary's time will be 1/3 John's time.

The time ratio for X and Y is as follows:
(X's time) : (Y's time) = 5 hours : 3 hours = 5:3.
Thus, the rate ratio for X and Y is the RECIPROCAL of the time ratio:
(X's rate) : (Y's rate) = 3:5.

The rate ratio implies the following:
Of every 8 miles that are traveled when X and Y move toward each other, X travels 3 miles, while Y travels 5 miles.
Since X travels 3 of every 8 miles, X will travel 3/8 of the 100 miles between the two trains:
X's distance = (3/8) * 100 = 37.5 miles.

The correct answer is A.
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by Mo2men » Wed Dec 27, 2017 12:01 pm
GMATGuruNY wrote:
AAPL wrote:Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5
Time and rate have a RECIPROCAL RELATIONSHIP.
If Mary works TWICE as fast as John, Mary's time will be 1/2 John's time.
If Mary works THREE TIMES as fast as John, Mary's time will be 1/3 John's time.

The time ratio for X and Y is as follows:
(X's time) : (Y's time) = 5 hours : 3 hours = 5:3.
Thus, the rate ratio for X and Y is the RECIPROCAL of the time ratio:
(X's rate) : (Y's rate) = 3:5.

The rate ratio implies the following:
Of every 8 miles that are traveled when X and Y move toward each other, X travels 3 miles, while Y travels 5 miles.
Since X travels 3 of every 8 miles, X will travel 3/8 of the 100 miles between the two trains:
X's distance = (3/8) * 100 = 37.5 miles.

The correct answer is A.
Dear Mitch,

Does you way of reasoning work for chasing problems? I find hard to apply. Do I miss something?

Thanks
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by GMATWisdom » Wed Dec 27, 2017 3:56 pm
AAPL wrote:Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5

The OA is A.

I don't have clear this PS question, I appreciate if any expert explain it for me. Thank you so much.
The two trains are travelling in oppsite drections at the speeds 100/5 and 100/3 mph
Their total distance travelled before they meet= 100 miles and their combined speed=100/5+100/3=800/15
Time taken for meeting= distance/speed =(100)/(800/15)=15/8 hours
distance travelled by train X = speed x time= (100/5)*(15/8)=20*15/8=300/8=37.5 milles

HENCE OPTION A
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by GMATGuruNY » Wed Dec 27, 2017 10:37 pm
Mo2men wrote:
GMATGuruNY wrote:
AAPL wrote:Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5
Time and rate have a RECIPROCAL RELATIONSHIP.
If Mary works TWICE as fast as John, Mary's time will be 1/2 John's time.
If Mary works THREE TIMES as fast as John, Mary's time will be 1/3 John's time.

The time ratio for X and Y is as follows:
(X's time) : (Y's time) = 5 hours : 3 hours = 5:3.
Thus, the rate ratio for X and Y is the RECIPROCAL of the time ratio:
(X's rate) : (Y's rate) = 3:5.

The rate ratio implies the following:
Of every 8 miles that are traveled when X and Y move toward each other, X travels 3 miles, while Y travels 5 miles.
Since X travels 3 of every 8 miles, X will travel 3/8 of the 100 miles between the two trains:
X's distance = (3/8) * 100 = 37.5 miles.

The correct answer is A.
Dear Mitch,

Does you way of reasoning work for chasing problems? I find hard to apply. Do I miss something?

Thanks
The approach above can be applied to rate problems in which elements WORK TOGETHER.
When trains travel toward each other -- as in the posted problem -- they work together to cover the distance between them.
Hence, the approach above is applicable.
In a chase-down problem, elements COMPETE rather than work together.
Hence, the approach above is not viable.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
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by Scott@TargetTestPrep » Wed Sep 04, 2019 5:20 pm
AAPL wrote:Two trains started simultaneously from opposite ends of a 100-mile route and traveled toward each other on parallel tracks. Train X, traveling at constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at constant rate, completed the 100-mile trip in 3 hours. How miles had X traveled when it met train Y?

A. 37.5
B. 40.0
C. 60.0
D. 62.5
E. 77.5

The OA is A.

I don't have clear this PS question, I appreciate if any expert explain it for me. Thank you so much.

The combined distance traveled of the two trains was 100 miles. Each train traveled for t hours. We can create the distance equation:

100/5 * t + 100/3 * t = 100

Multiplying by 15, we have:

300t + 500t = 1500

800t = 1500

t = 15/8

Thus, train X traveled 15/8 x 100/5 = 15/8 x 20 = 37.5 miles by the time it reached Y.

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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