Is 1/p > r/(r^2 + 2) ?
(1) p = r
(2) r > 0
Alternate approach:
Statement 2 is clearly INSUFFICIENT.
Statement 1: p=r
Substituting p=r into the question stem, we get:
1/r > r/(r² + 2)?
(1/r) - r/(r² + 2) > 0?
(r² + 2 - r²) / [r(r² + 2)] > 0?
2 / [r(r² + 2)] > 0?
1 / [r(r² + 2)] > 0?
Case 1: r>0
1 / [r(r² + 2)] > 0
1/(positive*positive) > 0
1/positive > 0.
positive > 0.
In this case, the answer is YES.
Case 2: r<0
1 / [r(r² + 2)] > 0
1/(negative*positive) > 0
1/negative > 0
negative > 0.
In this case, the answer is NO.
INSUFFICIENT.
Statements combined:
Since only Case 1 is possible, the answer to the question stem is YES.
SUFFICIENT.
The correct answer is
C.
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