This is a geometry problem so I will try my best to describe the figure shown.
You have two triangles shown, both with equal interior angles x, y, and z. So the triangles are similar because they have the same angles. The left triangle is drawn as larger than the right triangle. The base of the smaller triangle is shows as equaling s, and the base of the bigger triangle is show as equaling S.
If the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S = ?
Since the area of a triangle is 1/2 b * h
I come up with the equation 2*( 1/2 (s*h) ) = 1/2 (S*h)....I solve that and get S=2s
However the answer says that S = sqr_root(2)*s or (2^(1/2))s
What am I missing?
You have two triangles shown, both with equal interior angles x, y, and z. So the triangles are similar because they have the same angles. The left triangle is drawn as larger than the right triangle. The base of the smaller triangle is shows as equaling s, and the base of the bigger triangle is show as equaling S.
If the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S = ?
Since the area of a triangle is 1/2 b * h
I come up with the equation 2*( 1/2 (s*h) ) = 1/2 (S*h)....I solve that and get S=2s
However the answer says that S = sqr_root(2)*s or (2^(1/2))s
What am I missing?
