BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Triangle

Expert replies
Source: — Data Sufficiency |

by Bryant@VeritasPrep » Mon Sep 07, 2009 7:28 pm
the givens are insufficient because despite the figure "tricking" you into assuming RT is a straight line, it doesn't have to be. Picture a break in the figure where RS and ST come together. If that line is "bent," the angle x could be anything. Hope this helps.
Bryant Michaels
MBA Admissions Consultant


Enroll now. Pay later. Take advantage of Veritas Prep's flexible payment plan options
Join the discussion

IMO C

by enniguy » Mon Sep 07, 2009 9:10 pm
Please check the figure attached for explanation. Assume y and z to be the other angles adjacent to x. (x+y+z) will be 180 degrees.

1. The concepts being, equal sides will have equal opposite angles.

2. Adjacent angles on a line sum up to 180 degrees.

3. The sum of all the interior angles of a Quadrilateral 360 degrees.

So, the equation will be,

x + 180-y + 180-z + 90 = 360.

Solve,
x - y - z = -90.

2x - (x+y+z) = -90

2x - 180 = -90

x = 45.

Both the statement are needed to get this answer
Attachments
untitled.PNG
Join the discussion

Re: IMO C

by rish » Tue Sep 08, 2009 6:17 am
enniguy wrote:Please check the figure attached for explanation. Assume y and z to be the other angles adjacent to x. (x+y+z) will be 180 degrees.

1. The concepts being, equal sides will have equal opposite angles.

2. Adjacent angles on a line sum up to 180 degrees.

3. The sum of all the interior angles of a Quadrilateral 360 degrees.

So, the equation will be,

x + 180-y + 180-z + 90 = 360.

Solve,
x - y - z = -90.

2x - (x+y+z) = -90

2x - 180 = -90

x = 45.

Both the statement are needed to get this answer

Perfect. Thank You. OA is C
Join the discussion

Re: IMO C

by ispolef1 » Wed Sep 16, 2009 5:07 am
enniguy wrote:Please check the figure attached for explanation. Assume y and z to be the other angles adjacent to x. (x+y+z) will be 180 degrees.

1. The concepts being, equal sides will have equal opposite angles.

2. Adjacent angles on a line sum up to 180 degrees.

3. The sum of all the interior angles of a Quadrilateral 360 degrees.

So, the equation will be,

x + 180-y + 180-z + 90 = 360.

Solve,
x - y - z = -90.

2x - (x+y+z) = -90

2x - 180 = -90

x = 45.

Both the statement are needed to get this answer
where do you get the 2x in the highlighted statement from? I understand the rest, just cant figure that part out
Thanks
Join the discussion