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Triangle

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by jayhawk2001 » Wed Apr 11, 2007 9:12 pm
We have to use properties of similar triangles here.

Triangle QPS and Triangle PRS are similar triangles with right angle
at P and R respectively.

PR/QP = PS/QS

PR = QP * PS/QS
= 3 * 4 / 5
= 12/5
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by Cybermusings » Thu Apr 12, 2007 3:31 am
This one is pretty simple. Since the 2 sides are 3 (PQ) and 4 (PS) respectively, the hypotenuese QS becomes 5
Thus area of triangle PQS = 1/2 * 3 * 4 (taking PS as the base and PQ as the height)
1/2 * 5 * PR (taking QS as the base and PR as the height)
1/2*5*R = 1/2*3*4
Therefore R = 12/5
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