BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

triangle question

Expert replies
by Night reader » Mon Dec 20, 2010 2:35 am
In triangle ABC, MN is parallel with BC and AM/AB = 2/3. What is the ratio between the area of triangle AMN and the area of triangle ABC?

A. 2/3
B. 2/9
C. 4/5
D. 4/9
E. 5/9
Attachments
PIC.JPG
Join the discussion
Source: — Problem Solving |

by Rahul@gurome » Mon Dec 20, 2010 2:53 am
Image
Refer to the figure above,
Area of ABC = (1/2)*BC*AE
Area of AMN = (1/2)*MN*AD

As, AM/AB = 2/3 and MN parallel to BC,
  • 1. MN/BC = 2/3
    2. AD/AE = 2/3
Required ratio = (MN*AD)/(BC*AE) = (MN/BC)*(AD/AE) = (2/3)*(2/3) = 4/9

The correct answer is D.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by minar » Mon Dec 20, 2010 7:45 am
Rahul@gurome,
Your replies are always easy to understand. Thanks for that... :)
I have a quick question on the PS.

What about if I consider ABC and AMN both to be equilateral triangle?
If I do so, I get the same answer (D).
Is my approach wrong?
Join the discussion

by Rahul@gurome » Mon Dec 20, 2010 7:59 am
minar wrote:Rahul@gurome,
Your replies are always easy to understand. Thanks for that... :)
I'm glad to know that. :)
minar wrote:What about if I consider ABC and AMN both to be equilateral triangle?
If I do so, I get the same answer (D).
Is my approach wrong?
For this particular problem the logic is fine and it'll not cause any problem. But always try not to choose any special case. That can mislead you.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion