a-b+c>a+b-c?
You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?
St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF
1+2 we know b<c.
Confusing OA
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Source: Beat The GMAT — Data Sufficiency |
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mals24
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Even Im getting C
a-b+c>a+b-c?
You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?
St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF
1+2 we know b<c.
a-b+c>a+b-c?
You can cancel out 'a' from both sides. So you'll get c-b>b-c?
So basically the question is asking is c>b?
St 1 b is negative. No info about C INSUFF
St2: c is positive. No info about B INSUFF
1+2 we know b<c.
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parallel_chase
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vittalgmat
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OA should be C
looking at the question another way, it is asking
whether
-b +c > b -c ?
=> -(b -c) > b -c ?
This can only happen if we know b and c.
So C
looking at the question another way, it is asking
whether
-b +c > b -c ?
=> -(b -c) > b -c ?
This can only happen if we know b and c.
So C
unless i missed something, i got D
a-b+c > a+b-c
this comes to -b+c>b-c
c>2b-c
0>2b-2c
therefore c>b
a-(b-c)>a+(b-c)
a and subtracting any negative number will always be more than A + any negative number..however i am not sure if i have worked out the inequalities right.
a-b+c > a+b-c
this comes to -b+c>b-c
c>2b-c
0>2b-2c
therefore c>b
a-(b-c)>a+(b-c)
a and subtracting any negative number will always be more than A + any negative number..however i am not sure if i have worked out the inequalities right.
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ronniecoleman
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if a, b, c are integers, is a-b+c>a+b-c?
(i)b<0
(ii) c>0
Since b is negatvie
so -b > b
add anything a -b > a+ b
now if we add c ( which can be both positive or negative we don't know)
so II is required to understand the sign of c.
IMO C
OA is wrong!!
(i)b<0
(ii) c>0
Since b is negatvie
so -b > b
add anything a -b > a+ b
now if we add c ( which can be both positive or negative we don't know)
so II is required to understand the sign of c.
IMO C
OA is wrong!!
Admission champion, Hauz khaz
011-27565856
011-27565856
again, isnt a-(b-c)> a+(b-c)...we dont need any of the statements to figure that c>b..so b-c will always be negative...A minus a negative will be additive.ronniecoleman wrote:if a, b, c are integers, is a-b+c>a+b-c?
(i)b<0
(ii) c>0
Since b is negatvie
so -b > b
add anything a -b > a+ b
now if we add c ( which can be both positive or negative we don't know)
so II is required to understand the sign of c.
IMO C
OA is wrong!!
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vivek.kapoor83
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iamcste
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hypik21 wrote: again, isnt a-(b-c)> a+(b-c)...we dont need any of the statements to figure that c>b..so b-c will always be negative...A minus a negative will be additive.
Even with this, OA cant be "D" as you mentioned...
Infact, we have to answer this..and not take this as a fact
