If x,y,z are positive integers, x ≥y/3 and y + z ≥ 65 then the smallest possible value of x is
(a) 6
(b) 5
(c) 2
(d) 4
(e) 3[/list][/u]
(a) 6
(b) 5
(c) 2
(d) 4
(e) 3[/list][/u]
x ≥y/3 and y + z ≥ 65
So, since X is an integer, Y will be multiple of 3. Taking Y=3, x could be anything >= 1.
Y=3 also satisfies the second equation if Z is anything >= 62
So from the answer choices, it looks like it will be c
Somehow, I don't like my solution. Am I missing something here?
