Jinglander wrote:It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?
Speed of high speed train = z/x mph
Speed of regular train = z/y mph
Relative speed of the 2 trains = z/x + z/y
Time that will be taken for the trains to meet = z/(z/x + z/y) = z/{z(x+y)/xy)} = xy/(x + y)
Distance traveled by high speed train in time xy/(x + y) = Speed * Time = z/x * xy/(x + y) = zy/(x + y)
Distance traveled by regular train in time xy/(x + y) = Speed * Time = z/y * xy/(x + y) = zx/(x + y)
Difference between the distances = zy/(x + y) - zx/(x + y) =
z(y - x)/ (x +y)Rahul Lakhani
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