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Train A and Train B began traveling towards each other from

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Train A and Train B began traveling towards each other from

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Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM

OA E

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AAPL wrote:
Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM
This is a SHRINKING GAP question.

Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour,
35 mph + 25 mph = 60 mph
So, the gap CLOSES at a rate of 60 mph

Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM
We need to reduce the gap from 500 miles to 0 miles
In other words, we must close the gap a total of 500 miles

At what time did the trains meet?
time = distance/rate
= 500 miles/60 mph
= 50/6
= 25/3
= 8 1/3 hours
= 8 hours and 20 minutes

So, if the trains started at 1:00 pm, then the time the trains MET = 1:00 pm + (8 hours and 20 minutes)
= 9:20 pm

Answer: E

Cheers,
Brent

_________________
Brent Hanneson – Creator of GMATPrepNow.com
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Post
AAPL wrote:
Veritas Prep

Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM

OA E
We are given that Trains A and B traveled toward each other at 1 p.m. and that Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour. We are also given that they started 500 miles apart.

We can let the time of each train = t hours. Thus, the distance of Train A is 35t and the distance of Train B is 25t.

Let’s create the following equation to determine t:

distance of Train A + distance of Train B = total distance

35t + 25t = 500

60t = 500

t = 500/60 = 50/6 = 25/3 = 8 " hours = 8 hours and 20 minutes.

Thus, the trains met at 1 p.m. + 8 hours and 20 minutes = 9:20 p.m.

Alternate Solution:

Since the trains are moving towards each other, the distance between the two trains will decrease by 35 + 25 = 60 miles each hour. Since they were 500 miles apart, it will take them 500/60 = 25/3 = 8 1/3 hours or, 8 hours 20 minutes to meet. Thus, the trains meet at 1 p.m. + 8 hours and 20 minutes = 9:20 p.m.

Answer: E

_________________

Scott Woodbury-Stewart
Founder and CEO
scott@targettestprep.com



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