Find the number of trailing zeros in the expansion of (20!*21!*22! ......... *33!)^3!.
A. 468
B. 469
C. 470
D. 467
E. 471
Is it GMAT like question?
A. 468
B. 469
C. 470
D. 467
E. 471
Is it GMAT like question?
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The power of 3! = 6 indicates that the number of zeros = number of zeros in (20!*21!*...*33!) * 6rakeshd347 wrote:Find the number of trailing zeros in the expansion of (20!*21!*22! ......... *33!)^3!.
A. 468
B. 469
C. 470
D. 467
E. 471
Is it GMAT like question?
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