BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

tough Q from tatamcgraw

Expert replies
by harry_x1 » Tue Jun 26, 2007 9:49 am
in a village consisting of p persons, x% can read and write. Of the males alone y%, and of the females alone z% can read and write. Find the number of males in the village interms of p,x,y and z if z<y.

(a) p(x-z)/(y+x-z)

(b) p(x-z)/(y+x-2z)

(c) p(y-z)/(x-z)

(d) p(x-z)/(y-z)
Join the discussion
Source: — Problem Solving |

by givemeanid » Tue Jun 26, 2007 10:14 am
Let number of males = m
Since total 'p' persons, number of females = p - m

Now, x% of p = p*x/100
Number of males who can read and write = y% of m = m*y/100
Number of females who can read and write = z% of (p-m) = (p-m)*z/100

Total number who can read and write = Number of males who can read and write + Number of females who can read and write

px/100 = my/100 + (p-m)Z/100
Solving for m: m = p(x-z)/(y-z)

The answer is (d).
Join the discussion

by harry_x1 » Tue Jun 26, 2007 10:42 am
thanks givemeanid.....dats correct ans
Join the discussion