in a village consisting of p persons, x% can read and write. Of the males alone y%, and of the females alone z% can read and write. Find the number of males in the village interms of p,x,y and z if z<y.
(a) p(x-z)/(y+x-z)
(b) p(x-z)/(y+x-2z)
(c) p(y-z)/(x-z)
(d) p(x-z)/(y-z)
tough Q from tatamcgraw
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- givemeanid
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Let number of males = m
Since total 'p' persons, number of females = p - m
Now, x% of p = p*x/100
Number of males who can read and write = y% of m = m*y/100
Number of females who can read and write = z% of (p-m) = (p-m)*z/100
Total number who can read and write = Number of males who can read and write + Number of females who can read and write
px/100 = my/100 + (p-m)Z/100
Solving for m: m = p(x-z)/(y-z)
The answer is (d).
Since total 'p' persons, number of females = p - m
Now, x% of p = p*x/100
Number of males who can read and write = y% of m = m*y/100
Number of females who can read and write = z% of (p-m) = (p-m)*z/100
Total number who can read and write = Number of males who can read and write + Number of females who can read and write
px/100 = my/100 + (p-m)Z/100
Solving for m: m = p(x-z)/(y-z)
The answer is (d).