Why isn't it d?
ikant - '...so there is a possibility that the series may have infinite no of 1 in the beginning...'
--- it says that each term is the square of the preceding term, so we can't have ones otherwise we would never have anything but 1s in the sequence.
Stuart, you said that it's also possible that 6561 is the 5th term and that the 4th term is root(6561) or 81, that makes 3rd term 9, 2nd 3, and 1st root(3) which is not an integer anymore. With the last term being 6561, how can we have anything besides (3, 9, 81, 6561) or (-3, 9, 81, 6561)?
Am I seeing this wrong?