BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Tough DS

Expert replies
by rainmaker » Sat Aug 22, 2009 6:51 pm
Please explain your answer:

In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) sqrt(a^2) + sqrt(b^2) = sqrt(c^2) + sqrt(d^2)

where ^ means "raised to the power of"
Join the discussion
Source: — Data Sufficiency |

by iamjakekim » Sat Aug 22, 2009 10:08 pm
I think it is D

STM1.

if you cross multiply, you get b/a = d/c

STM2.

We need to know whether distance is equal.

For example, (1,4) and (4,1) are equal distance.
(-1,5) and (1,-5) are equal distance.!!

DDDDDD
Join the discussion

by shanrizvi » Sun Aug 23, 2009 1:48 pm
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

Statement 1: a/b = c/d

If (a,b) is (2,4) and (c,d) is (-2,-4), a/b = c/d and the points are equidistant. However, if (a,b) is (2,4) and (c,d) is (4,8), a/b = c/d but the points are not equidistant. Hence, the statement is insufficient.

Statement 2: sqrt(a^2) + sqrt(b^2) = sqrt(c^2) + sqrt(d^2)

For any point (x,y), the distant from the origin is sqrt(x^2+y^2). As this is NOT equal to sqrt(a^2) + sqrt(b^2), I say this statement is insufficient.

To prove this, plot any point (x,y) on the graph and consider the triangle bound by lines X=x, Y=y and the line from origin to (x,y). The distance to origin is the hypotenuse of the triangle with the other 2 sides of lengths x and y.
Join the discussion

by pradeepsarathy » Tue Aug 25, 2009 7:07 pm
IMO C

Stmt 1 - a/b = c/d

Case 1 - a = 1, b = 1, c = 2, d = 2
while a/b = c/d, the points are not equidistant from origin

Case 2 - a = -1, b = -1, c = 1, d = 1
a/b = c/d and also the points are equidistant from origin,
Hence stmt 1 alone is insufficient.
Eliminate answer choices A and D

Stmt 2 - sqrt(a^2) + sqrt(b^2) = sqrt(c^2) +sqrt(d^2)

Case 1 - a = 1, b = 2, c = 0, d = 3
while the points satisfy stmt 2, they are not equidistant from origin.

Case 2 - a = 1, b = 2, c = -1, d = -2
the points both satisfy the stmt 2 and also are equidistant from origin.

Hence stmt 2 alone is insufficient

Eliminate choice B.

Combining both stmt 1 and stmt 2 -
we see that the points have to be symmetrically oppisite to each other, and hence they will be equidistant from the origin as well.

Hence both stmts are sufficient.
Join the discussion