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Tom and Aly

Expert replies
by BTGmoderatorDC » Wed Oct 04, 2017 4:38 am
Tom and Aly purchased a laptop each at the same price. Both of them marked up the price of their laptops by the same amount. Aly sold her laptop by offering successive discounts of $200 and 20%, in that order; whereas Tom sold his laptop by offering the same scheme of discount but in reverse order. If the profit made by Aly was equal to the loss incurred by Tom, then what was the amount of profit (in $) made by Aly?
(A) $20
(B) $25
(C) $30
(D) $35
(E) $40

How will i start solving it? Is there an easy way or solution to this?

OA A
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Source: — Problem Solving |

by [email protected] » Wed Oct 04, 2017 9:45 am
Hi lheiannie07,

While this question involves a lot of information to keep track of, we can ultimately solve it by TESTing VALUES (albeit in a slightly "out-of-order" way).

To start, we have no idea what the original price of the laptops were and we don't know what the 'marked up' prices were. I'm going to start with the MARKED UP price and come back to the original price later on:

Marked Up Price = $1,000

Ally sold her laptop after giving a $200 discount, THEN a 20% off discount:
$1,000 - $200 = $800
$800 - (20% of $800) = $800 - $160 = $640

Tom sold his laptop after giving a 20% discount, THEN a $200 off discount:
$1,000 - (20% of $1000) = $1000 - $200 = $800
$800 - $200 = $600

We're told that Ally made a PROFIT that was EQUAL to Tom's LOSS. With sell prices of $640 and $600, respectively, the original purchase price would have had to have been $620

Ally = $640 - $620 = $20 profit
Tom = $600 - $620 = $20 loss

Thus, Ally's profit = $20

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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by BTGmoderatorDC » Wed Oct 04, 2017 1:59 pm
[email protected] wrote:Hi lheiannie07,

While this question involves a lot of information to keep track of, we can ultimately solve it by TESTing VALUES (albeit in a slightly "out-of-order" way).

To start, we have no idea what the original price of the laptops were and we don't know what the 'marked up' prices were. I'm going to start with the MARKED UP price and come back to the original price later on:

Marked Up Price = $1,000

Ally sold her laptop after giving a $200 discount, THEN a 20% off discount:
$1,000 - $200 = $800
$800 - (20% of $800) = $800 - $160 = $640

Tom sold his laptop after giving a 20% discount, THEN a $200 off discount:
$1,000 - (20% of $1000) = $1000 - $200 = $800
$800 - $200 = $600

We're told that Ally made a PROFIT that was EQUAL to Tom's LOSS. With sell prices of $640 and $600, respectively, the original purchase price would have had to have been $620

Ally = $640 - $620 = $20 profit
Tom = $600 - $620 = $20 loss

Thus, Ally's profit = $20

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Thanks a lot, this is a great help. Is this the easiest way to solve it?
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by [email protected] » Thu Oct 05, 2017 10:20 am
Hi lheiannie07,

You could certainly solve this question Algebraically, but there might be a point at which you don't know what to do next.... Let's call the sell price of each laptop X:

Aly: a $200 discount, then a 20% discount would give us....
(X - 200)(.8) = .8X - 160

Tom: a 20% discount, then a $200 discount would give us...
.8X - 200

When you compare the two prices, you'll notice that they are remarkably similar:
Aly = .8X - $160
Tom = .8X - $200

The difference in those two values is $40. From here, the last 'step' is to recognize that Aly's PROFIT is the SAME as Tom's LOSS, so that $40 difference would be a $20 profit for Aly and a $20 loss for Tom

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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Join the discussion

by Jeff@TargetTestPrep » Mon Dec 18, 2017 5:46 pm
lheiannie07 wrote:Tom and Aly purchased a laptop each at the same price. Both of them marked up the price of their laptops by the same amount. Aly sold her laptop by offering successive discounts of $200 and 20%, in that order; whereas Tom sold his laptop by offering the same scheme of discount but in reverse order. If the profit made by Aly was equal to the loss incurred by Tom, then what was the amount of profit (in $) made by Aly?
(A) $20
(B) $25
(C) $30
(D) $35
(E) $40
We can let p = the price of the laptops when Tom and Aly bought them and m = markup of the laptops. Thus, p + m = the price at which they originally wanted to sell the laptops. However, after the discounts, Aly sold her laptop at the price of (p + m - 200)(0.8) dollars and Tom sold his laptop at the price of 0.8(p + m) - 200 dollars. In dollars, the profit made by Aly is (p + m - 200)(0.8) - p and the loss incurred by Tom is p - (0.8(p + m) - 200). Since Aly's profit is equal to Tom's loss, we can create the following equation:

(p + m - 200)(0.8) - p = p - (0.8(p + m) - 200)

0.8p + 0.8m - 160 - p = p - 0.8p - 0.8m + 200

0.8m - 0.2p - 160 = 0.2p - 0.8m + 200

1.6m - 0.4p = 360

16m - 4p = 3600

4p = 16m - 3600

p = 4m - 900

At this point, we actually can make up a number for m (as long as p will be positive). For example, we can let m = 250, so p = 4(250) - 900 = 100. Thus, Aly's profit is:

(100 + 250 - 200)(0.8) - 100

(150)(0.8) - 100

120 - 100

20 dollars

Note: For any number we make up for m (as long as p will be positive), Aly's profit will always be $20.

Alternatively, we can substitute p = 4m - 900 in the equation for the profit of Aly:

Profit of Aly = (p + m - 200)(0.8) - p
= (4m - 900 + m -200)(0.8) - (4m - 900)
= (5m - 1100)(0.8) - 4m + 900
= 4m - 880 - 4m + 900
= 20

Answer: A

Jeffrey Miller
Head of GMAT Instruction
[email protected]

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by GMATGuruNY » Tue Dec 19, 2017 5:08 am
lheiannie07 wrote:Tom and Aly purchased a laptop each at the same price. Both of them marked up the price of their laptops by the same amount. Aly sold her laptop by offering successive discounts of $200 and 20%, in that order; whereas Tom sold his laptop by offering the same scheme of discount but in reverse order. If the profit made by Aly was equal to the loss incurred by Tom, then what was the amount of profit (in $) made by Aly?
(A) $20
(B) $25
(C) $30
(D) $35
(E) $40
Let the original selling price of each laptop = 500.

Aly sold her laptop by offering successive discounts of $200 and 20%, in that order.
After applying a $200 discount, we get:
500-200 = 300.
After applying a 20% discount, we get:
300 - (20% of 300) = 300 - 60 = 240.

Tom sold his laptop by offering the same scheme of discount but in reverse order.
After applying a 20% discount, we get:
500 - (20% of 500) = 500 - 100 = 400.
After applying a $200 discount, we get:
400-200 = 200.

The profit made by Aly was equal to the loss incurred by Tom
Let C = the cost price of each laptop.
Aly's profit = (Aly's selling price) - (cost price) = 240-C.
Tom's loss = (cost price) - (Tom's selling price) = C-200.
Since Aly's profit and Tom's loss are equal, we get:
240-C = C-200
440 = 2C
220 = C.

What was the amount of profit made by Aly?
Aly's profit = (Aly's selling price) - (cost price) = 240-220 = 20.

The correct answer is A.
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by BTGmoderatorDC » Wed Jan 10, 2018 12:23 am
GMATGuruNY wrote:
lheiannie07 wrote:Tom and Aly purchased a laptop each at the same price. Both of them marked up the price of their laptops by the same amount. Aly sold her laptop by offering successive discounts of $200 and 20%, in that order; whereas Tom sold his laptop by offering the same scheme of discount but in reverse order. If the profit made by Aly was equal to the loss incurred by Tom, then what was the amount of profit (in $) made by Aly?
(A) $20
(B) $25
(C) $30
(D) $35
(E) $40
Let the original selling price of each laptop = 500.

Aly sold her laptop by offering successive discounts of $200 and 20%, in that order.
After applying a $200 discount, we get:
500-200 = 300.
After applying a 20% discount, we get:
300 - (20% of 300) = 300 - 60 = 240.

Tom sold his laptop by offering the same scheme of discount but in reverse order.
After applying a 20% discount, we get:
500 - (20% of 500) = 500 - 100 = 400.
After applying a $200 discount, we get:
400-200 = 200.

The profit made by Aly was equal to the loss incurred by Tom
Let C = the cost price of each laptop.
Aly's profit = (Aly's selling price) - (cost price) = 240-C.
Tom's loss = (cost price) - (Tom's selling price) = C-200.
Since Aly's profit and Tom's loss are equal, we get:
240-C = C-200
440 = 2C
220 = C.

What was the amount of profit made by Aly?
Aly's profit = (Aly's selling price) - (cost price) = 240-220 = 20.

The correct answer is A.
Thanks a lot!
Join the discussion

by BTGmoderatorDC » Wed Jan 10, 2018 12:24 am
[email protected] wrote:Hi lheiannie07,

You could certainly solve this question Algebraically, but there might be a point at which you don't know what to do next.... Let's call the sell price of each laptop X:

Aly: a $200 discount, then a 20% discount would give us....
(X - 200)(.8) = .8X - 160

Tom: a 20% discount, then a $200 discount would give us...
.8X - 200

When you compare the two prices, you'll notice that they are remarkably similar:
Aly = .8X - $160
Tom = .8X - $200

The difference in those two values is $40. From here, the last 'step' is to recognize that Aly's PROFIT is the SAME as Tom's LOSS, so that $40 difference would be a $20 profit for Aly and a $20 loss for Tom

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Thanks a lot!
Join the discussion