Of the families

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alex.gellatly: Master | Next Rank: 500 Posts; Posts: 435; Joined: Wed Nov 16, 2011 7:27 amFollowed by: 16 members; Thanked: 48 times

by alex.gellatly » Sun Aug 26, 2012 12:38 am

Of the families in city X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998?

50%
52%
56%
70%
74%

Thanks

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Source: Beat The GMAT — Problem Solving | Sun Aug 26, 2012 12:38 am

rijul007: Legendary Member; Posts: 588; Joined: Sun Oct 16, 2011 9:42 amFollowed by: 9 members; Location: New Delhi, India; Thanked: 130 times; GMAT Score:720

by rijul007 » Sun Aug 26, 2012 2:01 am

alex.gellatly wrote:Of the families in city X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998?

50%
52%
56%
70%
74%

Thanks

Lets say there were 100 families in city X in 1994
No of families that owned the computer = 40

In 1998,
No of families that owned the computer = 40 + 30% of 40 = 52
Total no of families = 4% greater than in 1994 = 104

percent of the families in City X owned a personal computer in 1998 = 52/104 *100 = 50%

Option A

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neelgandham: Community Manager; Posts: 1060; Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members; Location: Utrecht, The Netherlands; Thanked: 318 times

by neelgandham » Sun Aug 26, 2012 2:02 am

1994
Let the total number of families in city X be X,
then the number of families who own a personal computer in city X = 0.4X

1998
Total number of families in city X = 1.04*X
The number of families who own a personal computer in city X = 1.3*0.4*X = 0.52*X

%age of families in City X who owned a personal computer in 1998 = (0.52*X/1.04*X)*100= 50%

Anil Gandham
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