M7MBA wrote:$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$
√12 + (√9 * √12) + (√4 * √12)
= √12 + 3√12 + 2√12
= 6√12
= 6 * √4 * √ 3
= 12√3
The correct answer is
A.
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