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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote To celebrate a colleague's retirement, the T coworkers in an This topic has 3 expert replies and 0 member replies Top Member To celebrate a colleague's retirement, the T coworkers in an Timer 00:00 Your Answer A B C D E Global Stats Difficult To celebrate a colleague's retirement, the T coworkers in an office agreed to share equally the cost of a catered lunch. If the lunch costs a total of x dollars and S of the coworkers fail to pay their share, which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute so that the cost of the lunch is completely paid? A. x/T B. x/(T-S) C. Sx/(T-S) D. Sx/T(T-S) E. X(T-S)/T OA D Source: GMAT Prep GMAT/MBA Expert GMAT Instructor Joined 22 Aug 2016 Posted: 1975 messages Followed by: 30 members Upvotes: 470 BTGmoderatorDC wrote: To celebrate a colleague's retirement, the T coworkers in an office agreed to share equally the cost of a catered lunch. If the lunch costs a total of x dollars and S of the coworkers fail to pay their share, which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute so that the cost of the lunch is completely paid? A. x/T B. x/(T-S) C. Sx/(T-S) D. Sx/T(T-S) E. X(T-S)/T OA D Source: GMAT Prep Desired share from each = X/T; The actual share of (T - S) coworkers = X/(T - S) Additional amount by each coworker = X/(T - S) - X/T = SX/T(T - S) The correct answer: D Hope this helps! -Jay _________________ Manhattan Review GMAT Prep Locations: GRE Manhattan | TOEFL Prep Courses San Diego | IELTS Prep Courses Denver | San Francisco ACT Tutoring | and many more... Schedule your free consultation with an experienced GMAT Prep Advisor! Click here. GMAT/MBA Expert GMAT Instructor Joined 25 May 2010 Posted: 15344 messages Followed by: 1864 members Upvotes: 13060 GMAT Score: 790 BTGmoderatorDC wrote: To celebrate a colleague's retirement, the T coworkers in an office agreed to share equally the cost of a catered lunch. If the lunch costs a total of x dollars and S of the coworkers fail to pay their share, which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute so that the cost of the lunch is completely paid? A. x/T B. x/(T-S) C. Sx/(T-S) D. Sx/T(T-S) E. X(T-S)/T The T coworkers in an office agreed to share equally the cost of a catered lunch. The lunch costs a total of X dollars. Let X=5 and T=5, implying that the original cost per worker = 5/5 =$1.

S of the coworkers fail to pay their share.
Which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute?

Let S=4, with the result that the 1 remaining worker must pay the entire $5. Since the share for the 1 remaining worker increases from$1 to $5 -- an increase of$4 -- the correct answer must yield 4 when X=5, T=5 and S=4.

Only D works:
SX/T(T-S) = (4*5)/(5 * 5-4) = 4

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BTGmoderatorDC wrote:
To celebrate a colleague's retirement, the T coworkers in an office agreed to share equally the cost of a catered lunch. If the lunch costs a total of x dollars and S of the coworkers fail to pay their share, which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute so that the cost of the lunch is completely paid?

A. x/T
B. x/(T-S)
C. Sx/(T-S)
D. Sx/T(T-S)
E. X(T-S)/T

OA D

Source: GMAT Prep
We are given that T coworkers agreed to equally split the payment for the cost of a lunch. We are also given that the lunch costs x dollars, and S coworkers do not pay their share.

We need to determine the ADDITIONAL AMOUNT that each coworker has to pay now.

The original cost per person for the lunch would have been x/T. Since S coworkers did not pay, the actual cost was x/(T-S). Thus, the additional amount paid was:

x/(T-S) - x/T

Getting a common denominator, which is T(T-S), we have:

T/T * x/(T-S) - (T-S)/(T-S) * (x/T)

xT/[T(T-S)] - x(T-S)/[T(T-S)]

[xT - xT + xS]/[T(T-S)]

xS/[T(T-S)]

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