A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the the distance in km?
A. 36
B. 38
C. 40
D. 42
E. 44
Ans : C
Need techniques to answer such questions in minimum time
Time and Speed
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In every case, the distance is THE SAME.coolhabhi wrote:A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the the distance in km?
A. 36
B. 38
C. 40
D. 42
E. 44
Since d = (rate)(time), we get:
(new rate)(new time) = (actual rate)(actual time).
If he had moved 3 kmph faster, he would have taken 40 minutes -- in other words, 2/3 hour -- less.
Since (new rate)(new time) = (actual rate)(actual time), we get:
(r + 3)(t - 2/3) = rt
rt - (2/3)r + 3t - 2 = rt
-(2/3)r + 3t = 2
-2r + 9t = 6.
If he had moved 2 kmph slower, he would have taken 40 minutes -- in other words, 2/3 hour -- more.
Since (new rate)(new time) = (actual rate)(actual time), we get:
(r - 2)(t + 2/3) = rt
rt + (2/3)r - 2t - (4/3) = rt
(2/3)r - 2t = 4/3
2r - 6t = 4.
Adding together the equations in blue, we get:
(-2r + 9t) + (2r - 6t) = 6+4
3t = 10
t = 10/3.
Substituting t = 10/3 into 2r - 6t = 4, we get:
2r - 6(10/3) = 4
2r - 20 = 4
2r = 24
r = 12.
Thus:
d = rt = (12)(10/3) = 40.
The correct answer is C.
This problem seems a bit too complex for the GMAT.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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