.rrobiinn wrote:If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?
I solved it just now. Couldn't find the post delete button.
What is the distance?
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I solved it just now. Couldn't find the post delete button.
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KapilKapoor
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Hi,
Assume speed of boy = b
Speed of car = c
time = distance/speed = 10/b = 25/c
=> b/c= 10/25
distance by b = time taken by c for travelling 1000 mtr * speed of b
time by c = 1000/c
Distance by b = 1000/c*b
1000*10/25 = 400 mtr
By the way what are the options.
Regards,
Kapil
Assume speed of boy = b
Speed of car = c
time = distance/speed = 10/b = 25/c
=> b/c= 10/25
distance by b = time taken by c for travelling 1000 mtr * speed of b
time by c = 1000/c
Distance by b = 1000/c*b
1000*10/25 = 400 mtr
By the way what are the options.
Regards,
Kapil
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Jim@StratusPrep
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Just divide 10 by 25 to get .4m
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Whenever you can rephrase a question to read, "For every X something else happens", we can typically solve the question using equivalent ratios.rrobiinn wrote:If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?
Here, we have "For every 10m a boy travels, a car travel 25m"
Here, we're comparing the boy's distance to the car's distance.
We want to know the number of meters the boy travels during the time the car travels 1km (1000m).
Let B = the number of meters the boy travels during the time the car travels 1000m
Equivalent ratios
boy's distance/car's distance: __ 10/25 = B/1000
To solve, cross multiply to get: 25B = (10)(1000)
Solve for B to get B=400m
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