tonker wrote:If xy=1, what is the value of
2 ^(x+y)^2 / 2 ^(x-y)^2 ?
a) 2
b) 4
c) 8
d) 16
e) 32
Let x=y=1.
Then:
2^(x+y)² / 2^(x-y)² = 2^(1+1)² / 2^(1-1)² = 2�/2� = 16/1 = 16.
The correct answer is
D.
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