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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## Three-fourths of the area of a rectangular lawn 30 feet wide tagged by: AbeNeedsAnswers ##### This topic has 3 expert replies and 1 member reply ## Three-fourths of the area of a rectangular lawn 30 feet wide ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the enclosure has full width and reduced length rather than full length and reduced width, how much less fence will be needed? A) 2 1/2 B) 5 C) 10 D) 15 E) 20 B Source: Official Guide 2020 ### GMAT/MBA Expert GMAT Instructor Joined 08 Dec 2008 Posted: 12982 messages Followed by: 1249 members Upvotes: 5254 GMAT Score: 770 AbeNeedsAnswers wrote: Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the enclosure has full width and reduced length rather than full length and reduced width, how much less fence will be needed? A) 2 1/2 B) 5 C) 10 D) 15 E) 20 B Source: Official Guide 2020 Here's a diagram of the 30 x 40 lawn If we keep the full width (of 30 feet), then the length of the enclosure = 3/4 of 40 = 30 feet So, the enclosure is a 30 by 30 square. The PERIMETER = 30 + 30 + 30 + 30 = 120 feet If we keep the full length (of 40 feet), then the width of the enclosure = 3/4 of 30 = 22.5 feet So, the enclosure is a 40 by 22.5 rectangle. The PERIMETER = 40 + 40 + 22.5 + 22.5 = 125 feet If the enclosure has full width and reduced length rather than full length and reduced width, how much less fence will be needed? 125 feet - 120 feet = [size=200]5[/size] Answer: B Cheers, Brent _________________ Brent Hanneson â€“ Creator of GMATPrepNow.com Use my video course along with Sign up for free Question of the Day emails And check out all of these free resources GMAT Prep Now's comprehensive video course can be used in conjunction with Beat The GMATâ€™s FREE 60-Day Study Guide and reach your target score in 2 months! ### Top Member Legendary Member Joined 29 Oct 2017 Posted: 965 messages Followed by: 4 members For each case, we determine the unknown dimension of the fence and calculate the perimeter of the fence. Case 1: $$30\cdot x=\frac{3}{4}\cdot 30 \cdot 40$$ $$x=30\,\Rightarrow\,P_1=4\cdot 120$$ Case 2: $$y\cdot 40 = \frac{3}{4}\cdot 30 \cdot 40$$ $$y=22.5\,\Rightarrow\, P_2=2(40+22.5)=125$$ Finally, we determine the difference between perimeters $$P_2-P_1=125-120=5$$ Therefore, the correct answer is __B__ ### GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2801 messages Followed by: 18 members Upvotes: 43 AbeNeedsAnswers wrote: Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the enclosure has full width and reduced length rather than full length and reduced width, how much less fence will be needed? A) 2 1/2 B) 5 C) 10 D) 15 E) 20 B Source: Official Guide 2020 If the enclosure has full width and reduced length, then the width = 30 ft and the reduced length = 40 x 3/4 = 30 ft. So we need 2(30) + 2(30) = 60 + 60 = 120 feet of the fence for the enclosure. On the other hand, if the enclosure has full length and reduced width, then the length = 40 ft and the reduced width = 30 x 3/4 = 22.5 ft. So we need 2(40) + 2(22.5) = 80 + 45 = 125 feet of the fence for the enclosure. Therefore, we see that we save 5 feet of fence in the first option. Answer: B _________________ Scott Woodbury-Stewart Founder and CEO scott@targettestprep.com See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews ### GMAT/MBA Expert Elite Legendary Member Joined 23 Jun 2013 Posted: 10197 messages Followed by: 496 members Upvotes: 2867 GMAT Score: 800 Hi All, We're told that 3/4 of the AREA of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. We're asked if the enclosure has full width and REDUCED length rather than full length and REDUCED width, how much LESS fence will be needed. This question is built around some standard Geometry and Arithmetic rules - and you might find that a couple of drawings can help you to stay organized. To start, the area of the FULL lawn is (30)(40) = 1200 square-feet. Three-quarters of that needs to be enclosed by a fence.... (3/4)(1200) = 3600/4 = 900 square-feet With full width, we would need the length to be 900/30 = 30 feet, meaning that we would have a 30 foot by 30 foot space. The length of THAT fence would be: 30 + 30 + 30 + 30 = 120 feet With full length, we would need the width to be 900/40 = 90/4 = 22.5 feet, meaning that we would have a 22.5 foot by 40 foot space. The length of THAT fence would be: 22.5 + 22.5 + 40 + 40 = 125 feet Thus, the difference in fence length would be 125 - 120 = 5 feet. Final Answer: B GMAT assassins aren't born, they're made, Rich _________________ Contact Rich at Rich.C@empowergmat.com • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Free Practice Test & Review How would you score if you took the GMAT Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • Award-winning private GMAT tutoring Register now and save up to$200

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