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A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve the

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A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve the

by BTGmoderatorDC » Mon Aug 24, 2020 6:21 pm

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A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320


OA A

Source: Princeton Review
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Re: A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve

by sjain296 » Mon Aug 24, 2020 11:08 pm
3 things have to be selected from 12 possible options

No of ways to do that = 12 C 3 = 220

Option A
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Re: A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve

by swerve » Tue Aug 25, 2020 12:45 pm
BTGmoderatorDC wrote: ↑
Mon Aug 24, 2020 6:21 pm
 A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320


OA A

Source: Princeton Review
Total ways of serving \(3\) canapes from a possible \(12\) combinations can be given by \(12c3\)

\(12c3 = \dfrac{12∗11∗10}{3∗2} = 220 \Longrightarrow\)A
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Re: A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve

by Scott@TargetTestPrep » Sat Sep 05, 2020 12:17 pm
BTGmoderatorDC wrote: ↑
Mon Aug 24, 2020 6:21 pm
 A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320


OA A

Solution:

The number of possible ways in which he can serve the 3 canapés from 12 is:

12C3 = (12 x 11 x 10)/(3 x 2) = 4 x 11 x 5 = 220

Answer: A

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