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This takes too long!!! Shortcuts?

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Source: — Problem Solving |

by Patrick_GMATFix » Mon Mar 03, 2014 3:07 pm
You're right, you're not supposed to actually calculate through brute force! This is a test of the common quadratic x^2 - y^2 = (x-y)(x+y). The answer is A. I go through the question in detail in the full solution below (taken from the GMATFix App).

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by GMATGuruNY » Mon Mar 03, 2014 4:44 pm
kobel51 wrote:(sqr(2)+1)*(sqr(2)-1)*(sqr(3)+1)*(sqr(3)-1) =

A) 2
B) 3
C) 2*sqr(6)
D) 5
E) 6

I thought about estimating but seems like there should be a faster way
Always be on the lookout for the following quadratic identities:
(a+b)² = a² + 2ab + b²
(a-b)² = a² - 2ab + b²
(a+b)(a-b) = a² - b².

The problem above is testing our ability to recognize the bottom identity, known as the DIFFERENCE OF TWO SQUARES:
(√2 + 1)(√2 - 1) * (√3 + 1)(√3 - 1)

= [ (√2)² - 1² ] * [ (√3)² - 1² ]

= (2-1)(3-1)

= 1*2

= 2.

The correct answer is A.
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by theCodeToGMAT » Mon Mar 03, 2014 10:31 pm
[(sqrt(2) + 1 ) (sqrt(2) - 1)] * [ (sqrt(3) + 1) (sqrt(3) - 1) ]

using formula (a+b)(a-b) = a^2 - b^2

= (2-1) * (3-1)

= 2

[spoiler]{A}[/spoiler]
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